The correct option for the value of vapour pressure of a solution at $45^{\circ} \mathrm{C}$ with be

Question

The correct option for the value of vapour pressure of a solution at $45^{\circ} \mathrm{C}$ with benzene to octane in molar ratio $3: 2$ is\ [At $45^{\circ} \mathrm{C}$ vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg . Assume ideal gas]\

Professor PC Thomas Classes · Answer

(d) : $P_{	ext {total }}=p_{	ext {benzene }} x_{	ext {benzene }}+p_{	ext {octane }} x_{	ext {octane }}$ $$ =280 	imes \frac{3}{5}+420 	imes \frac{2}{5}=168+168 $$ $=336 \mathrm{~mm}$ of Hg\