The van't Hoff factor (i) for a dilute aqueous solution of the strong electrolyte barium hydroxide i

Question

The van't Hoff factor (i) for a dilute aqueous solution of the strong electrolyte barium hydroxide is\

Professor PC Thomas Classes · Answer

(d) : Being a strong electrolyte, $\mathrm{Ba}(\mathrm{OH})_{2}$ undergoes $100 \%$ dissociation in a dilute aqueous solution, $$ \mathrm{Ba}(\mathrm{OH})_{2(a q)} ightarrow \mathrm{Ba}^{2+}{ }_{(a q)}+2 \mathrm{OH}^{-}{ }_{(a q)} $$ Thus, van't Hoff factor $i=3$.\