A 0.0020 m aqueous solution of an ionic compound $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5}\

Question

A 0.0020 m aqueous solution of an ionic compound $\left[\mathrm{Co}\left(\mathrm{NH}_{3}ight)_{5}\left(\mathrm{NO}_{2}ight)ight] \mathrm{Cl}$ freezes at $-0.00732^{\circ} \mathrm{C}$. Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be\ ( $K_{f}=-1.86^{\circ} \mathrm{C} / \mathrm{m}$ )\

Professor PC Thomas Classes · Answer

(d) : The number of moles of ions produced by 1 mol of ionic compound $=i$\ Applying, $\Delta T_{f}=i 	imes K_{f} 	imes m$\ $0.00732=i 	imes 1.86 	imes 0.002$\ $\Rightarrow i=\frac{0.00732}{1.86 	imes 0.002}=1.96 \approx 2$