In an experiment, mean free path of molecules of gas is found to be $9 imes 10^{-6} \mathrm{~m}$ a

Question

In an experiment, mean free path of molecules of gas is found to be $9 	imes 10^{-6} \mathrm{~m}$ and rms velocity is $4.5 	imes 10^{4} \mathrm{~m} / \mathrm{s}$. The collision frequency is given by\

Professor PC Thomas Classes · Answer

frequency of collision\ $=\frac{	ext { RMS velocity }}{	ext { Mean free path }}$\