To decrease the volume of a gas by $5 \%$ at constant temperature, the pressure should be\

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Professor PC Thomas Classes · Answer

Since the process is isothermal\ $\mathrm{P}_{0} \mathrm{~V}_{0}=\mathrm{PV}=\mathrm{P} 	imes 0.95 \mathrm{~V}_{0}$\ $\mathrm{P}_{0} \mathrm{~V}_{0}=\mathrm{P} 	imes 0.95 \mathrm{~V}_{0}$\ $\mathrm{P}=\frac{\mathrm{p}_{0}}{0.95} 	herefore \mathrm{P}=1.0526 \mathrm{P}_{0}$\ Change in pressure $=\left(\frac{\mathrm{P}}{\mathrm{P}_{0}}-1ight) 	imes 100$\ $=(1.0526-1) 	imes 100=5.26 \%$\