From the given list, the number of compounds with +4 oxidation state of sulphur is $\qquad$ -.\ $\m

Question

From the given list, the number of compounds with +4 oxidation state of sulphur is $\qquad$ -.\ $\mathrm{SO}_{3}, \mathrm{H}_{2} \mathrm{SO}_{3}, \mathrm{SOCl}_{2}, \mathrm{SF}_{4}, \mathrm{BaSO}_{4}, \mathrm{H}_{2} \mathrm{~S}_{2} \mathrm{O}_{7}$\

Professor PC Thomas Classes · Answer

(3) : Let $x$ be the oxidation state of $S$.\ $\stackrel{x}{\mathrm{~S}_{3}}: x-6=0 \quad$ or, $x=+6$\ $\mathrm{H}_{2} \mathrm{SO}_{3}:+2+x-6=0$ or, $x=+4$ \ $\stackrel{x}{\mathrm{~S} O C l} 2: x-2-2=0 \quad$ or, $x=+4$\ $\stackrel{x}{\mathrm{~S}_{4}} \quad: x-4=0 \quad$ or, $x=+4$\ $\mathrm{BaSO}_{4}:+2+x-8=0$ or, $x=+6$\ $\mathrm{H}_{2}{ }_{\mathrm{S}}^{2} \mathrm{O}_{7}:+2+2 x-14=0$ or, $x=+6$\