In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in p

Question

In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of $\mathrm{CO}_{2}$ is\

Professor PC Thomas Classes · Answer

(b) : $2 \mathrm{MnO}_{4}^{-}+5 \mathrm{C}_{2} \mathrm{O}_{4}^{2-} ightarrow 10 \mathrm{CO}_{2}$ $$ +2 \mathrm{Mn}^{2+}$$ Total 10 electrons are required for 10 $\mathrm{CO}_{2}$ molecules so, 1 electron per $\mathrm{CO}_{2}$ molecule.\