The points $\left(0, \frac{8}{3}\right),(1,3)$ and $(82,30)$ are vertices of

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Professor PC Thomas Classes · Answer

(d) : Let $A\left(0, \frac{8}{3}ight), B(1,3), C(82,30)$ Since slope of line $A B=\frac{1}{3}$, slope of $B C=\frac{1}{3}$\ $	herefore \quad$ Slope of $A B=$ slope of $B C 	herefore A B \| B C$ As $B$ is common point of $A B$ and $B C$\ $	herefore \quad A, B, C$ are collinear.\