The lines $2 x+3 y+19=0$ and $9 x+6 y-17=0$ cut the coordinate axes forming a

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True As $a_{1} x+b_{1} y+c_{1}=0$ and $a_{2} x+b_{2} y+c_{2}=0$ cuts the co-ordinate axes at concyclic points.\ $\Rightarrow \quad a_{1} a_{2}=b_{1} b_{2}$ or $\frac{a_{1}}{a_{2}}=-\frac{b_{1}}{b_{2}}$\ Here, $2 x+3 y+19=0$\ and $9 x+6 y-17=0 \Rightarrow\left(a_{1}=2, b_{1}=3ight.$, $\left.c_{1}=19ight)$ and ( $a_{2}=9, b_{2}=6, c_{2}=-17$ )\ $	herefore \quad a_{1} a_{2}=b_{1} b_{2}=18$\ Thus points are concyclic.