In a Zeisels method of estimation of alkoxy group 0.1 mole of an ether precipitated 47 g AgI. The nu

Question

In a Zeisels method of estimation of alkoxy group 0.1 mole of an ether precipitated 47 g AgI. The number of alkoxy groups in the ether is\

Professor PC Thomas Classes · Answer

$\mathrm{R}-\mathrm{O}-\mathrm{CH}_{3}+\mathrm{HI} ightarrow \mathrm{R}-\mathrm{OH}+\mathrm{CH}_{3} \mathrm{I}$\ $\mathrm{CH}_{3}-\mathrm{I}+\mathrm{AgOH} ightarrow \mathrm{CH}_{3} \mathrm{OH}+\mathrm{AgI}$\ Every mole AgI ( 235 g ) indicates 1 mole alkoxy group\ Here 0.1 mole produces 47 g AgI\ $	herefore 1$ mole produces $470 \mathrm{~g}=$ $$ \frac{470}{235}=2 	ext { mole } \mathrm{AgI} $$ $	herefore$ There are 2 alkoxy groups per molecules of the ether.\