Two SHM's with same amplitude and time period, when acting together in perpendicular directions with

Question

Two SHM's with same amplitude and time period, when acting together in perpendicular directions with a phase difference of $\pi / 2$, give rise to\

Professor PC Thomas Classes · Answer

(c) : $x=a \sin \omega t ; y=a \sin (\omega t+\pi / 2)=a \cos \omega t$ $$ x^{2}+y^{2}=a^{2} $$ It is an equation of a circle.\