Two simple harmonic motions of angular frequency 100 and $1000 \mathrm{rad} \mathrm{s}^{-1}$ have th

Question

Two simple harmonic motions of angular frequency 100 and $1000 \mathrm{rad} \mathrm{s}^{-1}$ have the same displacement amplitude. The ratio of their maximum acceleration is\

Professor PC Thomas Classes · Answer

(d) : $\omega_{1}=100 \mathrm{rad} \mathrm{s}^{-1} ; \omega_{2}=1000 \mathrm{rad} \mathrm{s}^{-1}$. Maximum acceleration of $(1)=-\omega_{1}{ }^{2} A$\ Maximum acceleration of $(2)=-\omega_{2}{ }^{2} \mathrm{~A}$\ $	herefore \frac{	ext { Acceleration (1) }}{	ext { Acceleration (2) }}=\frac{\omega_{1}^{2}}{\omega_{2}^{2}}=\frac{(100)^{2}}{^{2}}=\frac{1}{100}$\ $a(1): a(2)=1: 100$.\