A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of $31.4 \mathrm{~cm

Question

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of $31.4 \mathrm{~cm} / \mathrm{s}$. The frequency of its oscillation is\

Professor PC Thomas Classes · Answer

(d) : $a=5 \mathrm{~cm}, v_{	ext {max }}=31.4 \mathrm{~cm} / \mathrm{s}$ $$ v_{\max }=\omega a \Rightarrow 31.4=2 \pi v 	imes 5 $$ $\Rightarrow \quad 31.4=10 	imes 3.14 	imes v \Rightarrow v=1 \mathrm{~Hz}$\