A body executes simple harmonic motion with an amplitude $A$. At what displacement from the mean pos

Question

A body executes simple harmonic motion with an amplitude $A$. At what displacement from the mean position is the potential energy of the body is one fourth of its total energy?\

Professor PC Thomas Classes · Answer

(b) : P.E $=\frac{1}{2} M \omega^{2} x^{2}=\frac{1}{4}\left(\frac{1}{2} M \omega^{2} A^{2}ight) 	herefore \quad x=\frac{A}{2}$