The angular velocity and the amplitude of a simple pendulum is $\omega$ and a respectively. At a dis

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The angular velocity and the amplitude of a simple pendulum is $\omega$ and a respectively. At a displacement $x$ from the mean position if its kinetic energy is $T$ and potential energy is $V$, then the ratio of $T$ to $V$ is\

Professor PC Thomas Classes · Answer

(c) : P.E., $V=\frac{1}{2} m \omega^{2} x^{2}$\ and K.E., $T=\frac{1}{2} m \omega^{2}\left(a^{2}-x^{2}ight) 	herefore \quad \frac{T}{V}=\frac{a^{2}-x^{2}}{x^{2}}$