The equation of the line passing through the points of intersection of the circles $3 x^{2}+3 y^{2}-

Question

The equation of the line passing through the points of intersection of the circles $3 x^{2}+3 y^{2}-2 x+12 y-9=0$, and $x^{2}+y^{2}+6 x+2 y-15=0$ is

Professor PC Thomas Classes · Answer

Given equation of circles are $$\begin{equation*}x^{2}+y^{2}+6 x+2 y-15=0 	ag{1} \end{equation*}$$ or $3 x^{2}+3 y^{2}+18 x+6 y-45=0$\ and $3 x^{2}+3 y^{2}-2 x+12 y-9=0$\ Subtracting (2) from (1), we get $10 x-3 y-18=0$\