If the formula of Borax is $\mathrm{Na}_{2} \mathrm{~B}_{4} \mathrm{O}_{x}(\mathrm{OH})_{\gamma} \cd

Question

If the formula of Borax is $\mathrm{Na}_{2} \mathrm{~B}_{4} \mathrm{O}_{x}(\mathrm{OH})_{\gamma} \cdot z \mathrm{H}_{2} \mathrm{O}$, then $x+y+z=$ $\qquad$ -

Professor PC Thomas Classes · Answer

(17) : Formula of Borax is $\left[\mathrm{Na}_{2} \mathrm{~B}_{4} \mathrm{O}_{5}(\mathrm{OH})_{4}ight] \cdot 8 \mathrm{H}_{2} \mathrm{O}$\ Here $x=5, y=4, z=8$\ $x+y+z=5+4+8=17$\