Two waves having equation $$ \begin{aligned} & x_{1}=a \sin \left(\omega t-k x+\phi_{1} ight), \ &

Question

Two waves having equation $$ \begin{aligned} & x_{1}=a \sin \left(\omega t-k x+\phi_{1}ight), \ & x_{2}=a \sin \left(\omega t-k x+\phi_{2}ight) \end{aligned} $$ If in the resultant wave the frequency and amplitude remain equal to amplitude of superimposing waves, the phase difference between them is\

Professor PC Thomas Classes · Answer

(b) : Resultant amplitude $=2 a(1+\cos \phi)=a$\ $	herefore \quad(1+\cos \phi)=1 / 2 ; \cos \phi=-\frac{1}{2} ; \quad \phi=\frac{2 \pi}{3}$.\