The distance between source and observer is doubled. The intensity will become\

Question

Professor PC Thomas Classes · Answer

$\mathrm{l} \propto \frac{1}{\mathrm{~d}^{2}}$\ $I^{1} \propto \frac{1}{\left(2 d^{2}ight)}$\ $\frac{\mathrm{I}^{1}}{\mathrm{I}}=$\