Light traveling through air is incident on a liquid at angle $60^{\circ}$. If the refractive index o

Question

Light traveling through air is incident on a liquid at angle $60^{\circ}$. If the refractive index of the liquid is $\sqrt{3}$, the angle of deviation is\

Professor PC Thomas Classes · Answer

$\mathrm{n}=\frac{\sin \mathrm{i}}{\sin \mathrm{r}}$ $$ \begin{aligned} & \sqrt{3}=\frac{\sin 60}{\sin r} \ & \sin r=\frac{\sin 60}{\sqrt{3}}=\frac{1}{2} \end{aligned} $$ Deviation d = i - $\mathrm{r}=$\