A concentration cell is constructed by placing identical Cu electrodes in two $\mathrm{Cu}^{2+}$ sol

Question

A concentration cell is constructed by placing identical Cu electrodes in two $\mathrm{Cu}^{2+}$ solutions. If the concentrations of the two $\mathrm{Cu}^{2+}$ solutions are 1.0 M and 0.0020 M , The potential of the cell is nearly\

Professor PC Thomas Classes · Answer

$\mathrm{Cu} / \mathrm{Cu}^{2+}(0.002 \mathrm{M}) / / \mathrm{Cu}_{(1 \mathrm{M})}^{2+} / \mathrm{Cu}$.\ $\mathrm{E}=\mathrm{E}^{0}-\frac{0.0591}{\mathrm{n}} \log \frac{[\mathrm{P}]}{[\mathrm{R}]}$\ $\mathrm{E}^{0}$ of concentration is 0 .\ $	herefore \mathrm{E}=0-\frac{0.0591}{2} \log \frac{0.002}{1}$\ $=-0.03 \log 2 	imes 10^{-3}=-0.03 	imes-3-0.03 	imes \log 2$\ $=+0.09-0.03 	imes 0.3=0.09-0.009=0.081 \mathrm{~V}$\