The conductivity of $\mathrm{M} / 10 \mathrm{KCl}$ solution at $20^{\circ} \mathrm{C}$ is $0.0212 \m

Question

The conductivity of $\mathrm{M} / 10 \mathrm{KCl}$ solution at $20^{\circ} \mathrm{C}$ is $0.0212 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}$ and the resistance of cell containing this solution at $20^{\circ} \mathrm{C}$ is 55 ohm. The cell constant is\

Professor PC Thomas Classes · Answer

$K=\frac{1}{R} 	imes$ cell constant\ $=K 	imes R=0.0212 	imes 55=1.166 \mathrm{~cm}^{-1}$.\