In the electrochemical cell, $$ \mathrm{Mg}(\mathrm{~s})\left|\mathrm{Mg}_{(\mathrm{aq})}^{2+} \| \m

Question

In the electrochemical cell, $$ \mathrm{Mg}(\mathrm{~s})\left|\mathrm{Mg}_{(\mathrm{aq})}^{2+} \| \mathrm{Zn}_{(\mathrm{aq})}^{2+}ight| \mathrm{Zn}_{(\mathrm{s})} ; \mathrm{E}^{0}=+3.13 \mathrm{~V} $$ The correct plot of $\mathrm{E}_{	ext {cell }}$ versus $\log \frac{\left[\mathrm{Mg}^{2+}ight]}{\left[\mathrm{Zn}^{2+}ight]}$\ will be represented as:\ \ \ \

Professor PC Thomas Classes · Answer

For the given cell,\ $\mathrm{E}=\mathrm{E}^{0}-\frac{0.0591}{n} \log Q$ So a plot of E vs $\log \mathrm{Q}$ gives a line of negative slope. Ans : b)\