A charged particle of mass $m$ and charge $q$ is released from rest in an electric field E of unifor

Question

A charged particle of mass $m$ and charge $q$ is released from rest in an electric field E of uniform strength . The K.E. of the particle after time t is\

Professor PC Thomas Classes · Answer

$\mathrm{F}=\mathrm{qE} \quad \mathrm{a}=\frac{\mathrm{F}}{\mathrm{m}}=\frac{\mathrm{qE}}{\mathrm{m}}$\ $\mathrm{v}=\mathrm{u}+\mathrm{at}=0+\left(\frac{\mathrm{qE}}{\mathrm{m}}ight) \mathrm{t} \mathrm{KE}=\frac{1}{2} \mathrm{mv}^{2}$\ $=\frac{1}{2} m\left(\frac{q^{2} E^{2} t^{2}}{m^{2}}ight)=\frac{q^{2} E^{2} t^{2}}{2 m}$\