The intensity at a point due to a charge is inversely proportional to the\

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Professor PC Thomas Classes · Answer

Point charge $E \propto \frac{1}{r^{2}} V \propto \frac{1}{r}$ Dipole $\mathrm{E} \propto \frac{1}{\mathrm{r}^{3}} \mathrm{~V} \propto \frac{1}{\mathrm{r}^{2}}$\