At 400 K , the $\mathrm{t}_{1 / 2}$ of a gaseous reaction at the initial pressure of 80 kPa is 300 s

Question

At 400 K , the $\mathrm{t}_{1 / 2}$ of a gaseous reaction at the initial pressure of 80 kPa is 300 s . When the pressure is 40 kPa , the $\mathrm{t}_{1 / 2}$ is 150 s . The order of the reaction is\

Professor PC Thomas Classes · Answer

zero order, $\mathrm{t}_{1 / 2} \propto \mathrm{a}$.\