1 litre of 2 M acetic acid is mixed with one litre of 3 M ethyl alcohol, to form ester, as per the e

Question

1 litre of 2 M acetic acid is mixed with one litre of 3 M ethyl alcohol, to form ester, as per the equation $\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} ightarrow \mathrm{CH}_{3} \mathrm{COOC}_{2} \mathrm{H}_{5}+\mathrm{H}_{2} \mathrm{O}$. Assume that the reaction is $1^{	ext {st }}$ order both with respect to acid and alcohol. If each concentration is halved (before mixing) the initial rate would be --------times the present rate.\

Professor PC Thomas Classes · Answer

Rate $_{1}=\mathrm{k}$ [Acid][alcohol] $=\mathrm{k} 	imes 2 	imes 3$ Rate $_{2}=\mathrm{k} 	imes \frac{2}{2} 	imes \frac{3}{2}$ Hence 0.25 times Rate ${ }_{1}$\