The rate of a reaction doubles with $10^{0}$ rise in temperature (from 290 K to 300 K .) The activat

Question

The rate of a reaction doubles with $10^{0}$ rise in temperature (from 290 K to 300 K .) The activation energy, Ea for the reaction is approximately.\

Professor PC Thomas Classes · Answer

$\log \frac{\mathrm{k}_{2}}{\mathrm{k}_{1}}=-\frac{\mathrm{E}_{\mathrm{a}}}{2.303 \mathrm{R}} 	imes\left(\frac{1}{\mathrm{~T}_{2}}-\frac{1}{\mathrm{~T}_{1}}ight)$\ $\log 2=-\frac{\mathrm{E}_{\mathrm{a}}}{2.303 	imes 8.314} 	imes\left(\frac{1}{300}-\frac{1}{290}ight)$\ $\mathrm{Ea}=50140 \mathrm{~J}$\