For a chemical reaction $X \rightarrow Y$, rate increases by the factor 2.25 when concentration of $

Question

For a chemical reaction $X ightarrow Y$, rate increases by the factor 2.25 when concentration of $X$ is increased by 1.5 . The order is\

Professor PC Thomas Classes · Answer

Rate $1=\mathrm{k}[\mathrm{X}]^{\mathrm{n}}$ Rate $2=\mathrm{k}[1.5]^{\mathrm{n}} 	imes[\mathrm{X}]^{\mathrm{n}}$\ $\frac{	ext { Rate2 }}{	ext { Rate1 }}=(1.5)^{n=2.25}$\ $n=2,2^{	ext {nd }}$ order reaction. Rate $=\mathrm{k}[\mathrm{x}]^{2}$\