The compound 1, 2-butadiene has\

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(d) : $\stackrel{4}{\mathrm{C}} \mathrm{H}_{3}-\stackrel{3}{\mathrm{C}} \mathrm{H}=\stackrel{2}{\mathrm{C}}=\stackrel{1}{\mathrm{C}} \mathrm{H}_{2}$ From this we find the hybridisation of various carbon atoms as follows: $$ \mathrm{C}^{1}=s p^{2}, \mathrm{C}^{2}=s p, \mathrm{C}^{3}=s p^{2}, \mathrm{C}^{4}=s p^{3} $$