The separation of two coloured substances was done by paper chromatography. The distance travelled b

Question

The separation of two coloured substances was done by paper chromatography. The distance travelled by solvent front, substance $A$ and substance $B$ from the base line are $3.25 \mathrm{~cm}, 2.08 \mathrm{~cm}$ and 1.05 cm , respectively. The ratio of $R_{f}$ values of $A$ to $B$ is $\qquad$ -.\

Professor PC Thomas Classes · Answer

(2) : $R_{f}=\frac{	ext { Distance moved by the substance from base line }}{	ext { Distance moved by the solvent from base line }}$\ $R_{f}(A)=\frac{2.08}{3.25}$ and $R_{f}(B)=\frac{1.05}{3.25}$\ $	herefore \frac{R_{f}(A)}{R_{f}(B)}=\frac{2.08}{1.05}=1.98 \approx 2$