$\mathrm{X}=\mathrm{a}+\mathrm{bt}+\mathrm{ct}^{2}$ where x is in metre and t in seconds. The dimens

Question

$\mathrm{X}=\mathrm{a}+\mathrm{bt}+\mathrm{ct}^{2}$ where x is in metre and t in seconds. The dimensions of $\mathrm{a}, \mathrm{b}$ and c are\

Professor PC Thomas Classes · Answer

If $\mathrm{A}=\mathrm{B}+\mathrm{C}+\mathrm{D}$ DF of $\mathrm{A}=\mathrm{DF}$ of $\mathrm{B}=\mathrm{DF}$ of $\mathrm{C}=\mathrm{DF}$ of D\ Df of $\mathrm{a}=\mathrm{DF}$ of $\mathrm{x}=\mathrm{L}$\ DF of $\mathrm{bt}=\mathrm{L}$\ DF of $b=\frac{L}{t}=\frac{L}{T}=L T^{-1}$\ DF of $\mathrm{ct}^{2}=\mathrm{L}$\ DF of $\mathrm{c}=\frac{\mathrm{L}}{\mathrm{t}^{2}}=\frac{\mathrm{L}}{\mathrm{T}^{2}}=\mathrm{LT}^{-2}$\