The reciprocal of the square of the limit $\lim _{x \rightarrow 1}\left[\frac{x-1}{2 x^{2}-7 x+5}\ri

Question

The reciprocal of the square of the limit $\lim _{x \rightarrow 1}\left[\frac{x-1}{2 x^{2}-7 x+5}\right]$

Professor PC Thomas Classes · Answer

$\lim _{x ightarrow 1}\left[\frac{(x-1)}{(x-1)(2 x-5)}ight]$\ $=\lim _{x ightarrow 1}\left(\frac{1}{2 x-5}ight)=-\frac{1}{3}$\ ( $\because x-1 
eq 0$ when $x$ tends to 1 )\