The resistance of 12 ohm has ' $\ell$ ' as its length and ' $a$ ' as its cross-section, and, another

Question

The resistance of 12 ohm has ' $\ell$ ' as its length and ' $a$ ' as its cross-section, and, another resistance of same material has $4 \ell$ as length $4 a$ as its cross-section. How much is the new resistance\

Professor PC Thomas Classes · Answer

$R=\frac{ho L}{A}$\ $12=\frac{ho l}{a}$\ $R=\frac{ho(4 \ell)}{4 a}=$\