If 5 resistance of 2 ohm each, connected in series, across a cell of P.D. of 5 volt give a current o

Question

If 5 resistance of 2 ohm each, connected in series, across a cell of P.D. of 5 volt give a current of about 0.42 ampere, what is the internal resistance of the cell\

Professor PC Thomas Classes · Answer

$I=\frac{E}{R+r} \quad E=5 V$ $$ \begin{aligned} & \mathrm{R}=5 	imes 2=10 \Omega \ & \mathrm{I}=0.42 \mathrm{~A} \ & \mathrm{r}=? \end{aligned} $$ Solve.\