A potentiometer has 2 volt battery and no resistance in the primary. If the length is 10 m , what is

Question

A potentiometer has 2 volt battery and no resistance in the primary. If the length is 10 m , what is the balancing length for a Daniel cell of e mf 1.08 volt\

Professor PC Thomas Classes · Answer

p.d over 10 m ie. $1000 \mathrm{~cm}=2 \mathrm{~V}$\ p.d over $1 \mathrm{~cm}=\frac{2 \mathrm{~V}}{1000 \mathrm{~cm}}=\mathrm{e}$\ $\mathrm{E}=\ell \mathrm{e}$ where E is the e.m.f. balanced\ $\ell=$ length of potentiometer wire.\ $\mathrm{e}=\mathrm{p} . \mathrm{d}$ over unit length (Potential gradient). Here E = 1.08 V\ $\mathrm{e}=\frac{2 \mathrm{~V}}{1000 \mathrm{~cm}}$\ Solve\