Resistance of a conductor increase with the rise in temperature. This is due to\

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Professor PC Thomas Classes · Answer

$R=\frac{ho L}{A} \quad ho=\frac{m}{n^{2} 	au}$\ $	herefore \mathrm{R}=\frac{\mathrm{mL}}{\mathrm{ne}^{2} 	au \mathrm{~A}}$\ $	au$ is relaxation time. When temperature increases $	au$ decreases and R increases.\