In a Wheatstone bridge the resistance in the ratio arms are $100 \Omega$ and $150 \Omega$ respective

Question

In a Wheatstone bridge the resistance in the ratio arms are $100 \Omega$ and $150 \Omega$ respectively. If $\mathrm{R}=80 \Omega$, the resistance of the fourth arm will be\

Professor PC Thomas Classes · Answer

In a Wheatstones bridge $$ \mathrm{P}=100 \Omega $$ $\frac{P}{Q}=\frac{R}{X}$ $\mathrm{Q}=150 \Omega$ $$ \mathrm{R}=80 \Omega $$