An electron is moving round the nucleus of a hydrogen atom in a circular orbit of radius $r$. The Co

Question

An electron is moving round the nucleus of a hydrogen atom in a circular orbit of radius $r$. The Coulomb force $\vec{F}$ between the two is\ $\left(ight.$ where $\left.K=\frac{1}{4 \pi \varepsilon_0}ight)$

Professor PC Thomas Classes · Answer

(d) : The charge on hydrogen nucleus $q_{1}=+e$\ charge on electron, $q_{2}=-e$\ Coulomb force, $F=K \frac{q_{1} q_{2}}{r^{2}}=K \frac{(+e)(-e)}{r^{2}}$ $$ \vec{F}=-\frac{K e^{2}}{r^{3}} \vec{r}=-\frac{K e^{2}}{r^{2}} \hat{r} $$