In the nucleus of ${ }_{11} \mathrm{Na}^{23}$, the number of protons, neutrons and electrons are\

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Professor PC Thomas Classes · Answer

(a) : $Z=11$ i.e., number of protons $=11, A=23$\ $	herefore \quad$ Number of neutrons $=A-Z=12$\ Number of electron $=0$ (No electron in nucleus)\ Therefore 11, 12, 0 is the correct answer.