Two nuclei have their mass numbers in the ratio of $1: 3$. The ratio of their nuclear densities woul

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Two nuclei have their mass numbers in the ratio of $1: 3$. The ratio of their nuclear densities would be\

Professor PC Thomas Classes · Answer

(b) $: A_{1}: A_{2}=1: 3$ Their radii will be in the ratio $$ R_{0} A_{1}^{1 / 3}: R_{0} A_{2}^{1 / 3}=1: 3^{1 / 3} $$ Density $=\frac{A}{\frac{4}{3} \pi R^{3}}$\ $	herefore \quad ho_{A_{1}}: ho_{A_{2}}=\frac{1}{\frac{4}{3} \pi R_{0}^{3} \cdot 1^{3}}: \frac{3}{\frac{4}{3} \pi R_{0}{ }^{3}\left(3^{1 / 3}ight)^{3}}=1: 1$\ Their nuclear densities will be the same.\