The radius of germanium $(\mathrm{Ge})$ nuclide is measured to be twice the radius of ${ }_{4}^{9} \

Question

The radius of germanium $(\mathrm{Ge})$ nuclide is measured to be twice the radius of ${ }_{4}^{9} \mathrm{Be}$. The number of nucleons in Ge are\

Professor PC Thomas Classes · Answer

(a) : Nuclear radii $R=R_{0}(A)^{1 / 3}$, where $R_{0} \approx 1.2 \mathrm{fm}$\ or $R \propto(A)^{1 / 3}$\ $	herefore \quad \frac{R_{\mathrm{Be}}}{R_{\mathrm{Ge}}}=\frac{(9)^{1 / 3}}{(A)^{1 / 3}}$ or, $\frac{R_{\mathrm{Be}}}{2 R_{\mathrm{Be}}}=\frac{(9)^{1 / 3}}{(A)^{1 / 3}}\left(\becauseight.$ given $\left.R_{\mathrm{Ge}}=2 R_{\mathrm{Be}}ight)$\ or, $(A)^{1 / 3}=2 	imes(9)^{1 / 3}$\ or, $A=2^{3} 	imes 9=8 	imes 9=72$\ $	herefore \quad$ The number of nucleons in Ge is 72\