The mass number of He is 4 and that of sulphur is 32. The radius of sulphur nucleus is larger than t

Question

The mass number of He is 4 and that of sulphur is 32. The radius of sulphur nucleus is larger than that of helium by the factor of\

Professor PC Thomas Classes · Answer

(b) : Mass number of helium $\left(A_{\mathrm{He}}ight)=4$ and mass number of sulphur $\left(A_{\mathrm{S}}ight)=32$.\ Radius of nucleus, $r=r_{0}(A)^{1 / 3}$. Therefore $$ \frac{r_{\mathrm{s}}}{{ }^{{ }_{\mathrm{He}}}}=\left(\frac{A_{\mathrm{s}}}{A_{\mathrm{He}}}ight)^{1 / 3}=\left(\frac{32}{4}ight)^{1 / 3}=(8)^{1 / 3}=2 $$