The ratio of the radii of the nuclei ${ }_{13} \mathrm{Al}^{27}$ and ${ }_{52} \mathrm{Te}^{125}$ is

Question

The ratio of the radii of the nuclei ${ }_{13} \mathrm{Al}^{27}$ and ${ }_{52} \mathrm{Te}^{125}$ is approximately\

Professor PC Thomas Classes · Answer

(a) $: R \propto(A)^{1 / 3}$ from $R=R_{0} A^{1 / 3}$\ $	herefore \quad R_{\mathrm{A} 1} \propto(27)^{1 / 3}$ and $R_{\mathrm{Te}} \propto(125)^{1 / 5} \quad 	herefore \quad \frac{R_{\mathrm{A} 1}}{R_{\mathrm{Te}}}=\frac{3}{5}=\frac{6}{10}$\