In a $\beta$ - decay\

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Professor PC Thomas Classes · Answer

$\quad \beta$ decay is represented by the following equation ${ }_{z} X^{A} ightarrow Y_{z+1}^{A}+e_{-1}^{0}+\bar{r}$ \ Parent atom has Z protons and\ A-Z neutrons\ Daughter atom has $\mathrm{Z}+1$ protons and\ $\mathrm{A}-(\mathrm{Z}+1)$ neutrons .ie 1 proton more than X and 1 neutron less.\ $(\bar{v})$ is called anti neutrino. Here a neutron of the nucleus is converted in to proton and an electron\ $\mathrm{n} ightarrow \mathrm{P}+\mathrm{e}+\overline{\mathrm{v}}$\