What is the binding energy per nucleon for ${ }_{8} 0^{16}$ ? Given mass of ${ }_{8} 0^{16}=15.9949$

Question

What is the binding energy per nucleon for ${ }_{8} 0^{16}$ ? Given mass of ${ }_{8} 0^{16}=15.9949$ a.m.u \ Mass of proton $=1.007825$ a.m.u\ Mass of neutron=1.008665 a.m.u\

Professor PC Thomas Classes · Answer

Mass of $8 p+8 n=8(p+n)$\ $=8(1.007825+1.008665) \mathrm{amu}=\mathrm{x}$\ Mass of ${ }_{8} \mathrm{O}^{16}=15.9949 \mathrm{amu}=\mathrm{y}$\ Binding energy $=(x-y) 	imes 931 \mathrm{MeV}$\ Binding energy / nucleon $=\frac{(\mathrm{x}-\mathrm{y}) 931}{16} \mathrm{MeV}$\