The nuclear radius of a certain nucleus is 7.2 fm and it has a charge of $1.28 imes 10^{-17} \math

Question

The nuclear radius of a certain nucleus is 7.2 fm and it has a charge of $1.28 	imes 10^{-17} \mathrm{C}$. The number of neutrons inside the nucleus is\

Professor PC Thomas Classes · Answer

The nuclear radius is given by $R=R_{0} A^{1 / 3}$ where $R_{0}=1.2 \mathrm{fm}$\ $\mathrm{R}=7.2 \mathrm{fm}$\ $	herefore \mathrm{A}=\left(\frac{7.2}{1.2}ight)^{3}=216$\ Number of protons $=\frac{1.28 	imes 10^{-17}}{1.6 	imes 10^{-19}}=80$\ $	herefore$ Number of neutrons $=216-80=136$\