The force between the plates of a parallel plate capacitor with potential difference V between its p

Question

The force between the plates of a parallel plate capacitor with potential difference V between its plates separated by distance ' d ' is\

Professor PC Thomas Classes · Answer

Let F be the force between the plates which assumed as constant over a distance d . The work done in producing the separation $\mathrm{W}=\mathrm{Fd}$. It is converted into $\mathrm{PE}=\frac{1}{2} \mathrm{CV}^{2}$.\ $\mathrm{Fd}=\frac{1}{2} \mathrm{CV}^{2}$\ $	herefore \mathrm{F}=$