Two capacitors of $2 \mu \mathrm{f}$ and $3 \mu \mathrm{f}$ are connected in series the outer plate

Question

Two capacitors of $2 \mu \mathrm{f}$ and $3 \mu \mathrm{f}$ are connected in series the outer plate of first is at 1000 V , the outer plate, of second is earthed. The potential of inner plate of each capacitor is\

Professor PC Thomas Classes · Answer

$\mathrm{C}_{1}\left(\mathrm{~V}-\mathrm{V}_{1}ight)=\mathrm{C}_{2}\left(\mathrm{~V}_{1}-\mathrm{V}_{2}ight)$\ $\mathrm{V}=1000 \mathrm{~V}, \mathrm{~V}_{1}=$ Potential of the inner plate, $\mathrm{V}_{2}=$ 0 (Since the plate is earthed)\