A soap bubble is charged to a potentialof 16 V . Its radius is then doubled. The potential of the bu

Question

A soap bubble is charged to a potentialof 16 V . Its radius is then doubled. The potential of the bubble now will be\

Professor PC Thomas Classes · Answer

$\mathrm{V} \propto \frac{1}{\mathrm{r}}$\ $	herefore \mathrm{V}_{1} \propto \frac{1}{\mathrm{r}}$ and $\mathrm{V}_{2} \propto \frac{1}{\mathrm{r}_{2}}$\ $	herefore \frac{\mathrm{V}_{1}}{\mathrm{~V}_{2}}=\frac{\mathrm{r}_{2}}{\mathrm{r}_{1}} \Rightarrow \frac{16}{\mathrm{~V}_{2}}=\frac{2 \mathrm{r}_{1}}{\mathrm{r}_{1}} \Rightarrow \mathrm{~V}_{2} \frac{16}{2}$\